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WBMSC AE Civil 2016 question paper with answers

All 100 questions from the WBMSC (KMC) Assistant Engineer (degree) Civil paper — Assistant Engineer (Civil) — 2016 — with the correct answer and a short explanation under each one. Tap Show answer after you have tried a question, or take it as a timed mock test scored +2 / −1 like the real exam.

PaperAssistant Engineer (Civil) — 2016
PostAssistant Engineer (degree)
Questions100
Marking+2 for a right answer, −1 for a wrong one; 90 minutes
Answers on this pageAll 100

Questions

Q1.Increase in compactive effort causes

  1. Increase in optimum moisture content and decrease in dry unit weight
  2. Increase in both optimum moisture content and dry unit weight
  3. Decrease in optimum moisture content and increase in dry unit weight
  4. Decrease in both optimum moisture content and dry unit weight
Show answer

Answer: (c) Decrease in optimum moisture content and increase in dry unit weight

Higher compactive effort packs particles more densely at a lower water content — dry unit weight rises, OMC falls.

Q2.Area ratio of a sampler should be

  1. Less than 5%
  2. Greater than 5%
  3. Less than 10%
  4. Greater than 10%
Show answer

Answer: (c) Less than 10%

IS code criterion for a good (near-undisturbed) sampler is an area ratio under 10%, so soil disturbance stays low.

Q3.Normal consistency of ordinary Portland cement is about

  1. 10%
  2. 20%
  3. 30%
  4. 40%
Show answer

Answer: (c) 30%

Normal consistency of OPC is typically 26-33%, so ~30% is the standard textbook figure.

Q4.Slump recommended for mass concrete is about

  1. 25 to 50 mm
  2. 50 to 100 mm
  3. 100 to 125 mm
  4. 125 to 150 mm
Show answer

Answer: (a) 25 to 50 mm

Mass concrete needs low workability to control heat of hydration and shrinkage; 25-50 mm slump is typical.

Q5.If Kx and Kz are the permeabilities in x and z directions respectively, effective permeability is given by

  1. Ke = √(Kx·Kz)
  2. Ke = Kx + Kz
  3. Ke = Kx / Kz
  4. Ke = Kx − Kz
Show answer

Answer: (a) Ke = √(Kx·Kz)

Effective permeability for flow across stratified layers uses the geometric mean, Ke = √(KxKz).

Q6.If the Mohr's circle for a given stress condition touches the failure envelope

  1. The soil is stable
  2. Incipient failure occurs
  3. Soil has failed
  4. None of these
Show answer

Answer: (b) Incipient failure occurs

A Mohr circle just touching the failure envelope means stress is exactly at the failure condition — incipient failure, not yet failed.

Q7.Earth pressure on a wall due to 'at rest' condition is

  1. Greater than active as well as passive pressure
  2. Greater than active and less than passive pressure
  3. Less than active as well as passive pressure
  4. Less than active and greater than passive pressure
Show answer

Answer: (b) Greater than active and less than passive pressure

At-rest earth pressure coefficient K0 always lies between the active (Ka) and passive (Kp) values.

Q8.Maximum angle β of an infinite slope in a purely cohesionless soil is

  1. β = φ, angle of internal friction
  2. β = φ/2
  3. β = φ/3
  4. Not related to φ
Show answer

Answer: (a) β = φ, angle of internal friction

For a cohesionless soil, the maximum stable infinite-slope angle equals the angle of internal friction φ (FS=1 when β=φ).

Q9.Crushing strength of a first class brick should not be less than

  1. 3.5 N/mm²
  2. 7.0 N/mm²
  3. 10.5 N/mm²
  4. 14.0 N/mm²
Show answer

Answer: (c) 10.5 N/mm²

IS 1077 specifies a minimum crushing strength of 10.5 N/mm² for first class bricks.

Q10.Nominal size of modular brick is

  1. 190 mm x 90 mm x 90 mm
  2. 190 mm x 190 mm x 90 mm
  3. 200 mm x 100 mm x 100 mm
  4. 200 mm x 200 mm x 100 mm
Show answer

Answer: (c) 200 mm x 100 mm x 100 mm

Nominal modular brick size (brick + 10mm mortar joint) is 200 × 100 × 100 mm; actual size is 190×90×90mm.

Q11.Number of bricks required for one cubic metre of brick masonry is

  1. 400
  2. 450
  3. 500
  4. 550
Show answer

Answer: (c) 500

About 500 modular bricks are needed per cubic metre of brick masonry, accounting for mortar joints.

Q12.Angle of intersection of two plane mirrors of an optical square is

  1. 30°
  2. 45°
  3. 60°
  4. 90°
Show answer

Answer: (b) 45°

An optical square's mirrors are set at 45° to each other, giving a 90° deviation of the sighted ray.

Q13.If the true bearing of a line AB is 269°30', the azimuth of line AB is

  1. 0°30'
  2. 89°30'
  3. 90°30'
  4. 269°30'
Show answer

Answer: (d) 269°30'

Azimuth and whole-circle/true bearing are the same quantity measured clockwise from north, so the azimuth equals the given bearing, 269°30'.

Q14.Most commonly used retarder in cement is

  1. Gypsum
  2. Calcium chloride
  3. Calcium carbonate
  4. None of the above
Show answer

Answer: (a) Gypsum

Gypsum is interground with clinker specifically to retard the otherwise near-instant setting of cement.

Q15.Percentage of carbon content in mild steel is

  1. Less than 0.25
  2. Between 0.25 and 0.7
  3. Between 0.7 and 1.5
  4. Greater than 1.5
Show answer

Answer: (a) Less than 0.25

Mild steel is classified by a carbon content below about 0.25%.

Q16.Slenderness ratio for masonry walls should not be more than

  1. 10
  2. 20
  3. 30
  4. 40
Show answer

Answer: (c) 30

IS 1905 limits the effective slenderness ratio of load-bearing masonry walls/columns to around 27; among the given options, 30 is closest.

Q17.To make one cubic metre of 1:2:4 by volume concrete, volume of coarse aggregate required is

  1. 0.95m
  2. 0.85 m3
  3. 0.75 m3
  4. 0.65 m3
Show answer

Answer: (b) 0.85 m3

For 1:2:4 concrete, dry volume ≈ 1.54 m³ per m³ of wet concrete; coarse aggregate share (4/7) works out to about 0.85 m³.

Q18.Surkhi is added to lime mortar to

  1. Prevent shrinkage
  2. Decrease setting time
  3. Increase volume
  4. Impart hydraulicity
Show answer

Answer: (d) Impart hydraulicity

Surkhi (burnt clay/brick powder) reacts with fat lime to give it hydraulic (water-setting) properties.

Q19.Minimum reinforcement required in design of slabs is

  1. 0.10 per cent
  2. 0.15 per cent
  3. 0.20 per cent
  4. 0.30 percent
Show answer

Answer: (b) 0.15 per cent

0.15% of the gross cross-section is the traditional minimum slab reinforcement (mild steel) requirement.

Q20.In a rectangular beam section subjected to torsion, maximum shear stress occurs

  1. At the edge of wider face
  2. At the middle of wider face
  3. At the edge of shorter face
  4. At the middle of shorter face
Show answer

Answer: (b) At the middle of wider face

For a rectangular section under torsion, St. Venant's theory places maximum shear stress at the middle of the longer (wider) face.

Q21.Lateral ties provided in a column prevent

  1. Tension
  2. Compression
  3. Bending
  4. None of these
Show answer

Answer: (b) Compression

Lateral ties confine the core and restrain the longitudinal bars, letting the column develop its full compressive capacity.

Q22.In limit state design of concrete structures, the maximum limit imposed by IS codes on redistribution of moments in statically indeterminate beams is

  1. 10%
  2. 15%
  3. 20%
  4. 30%
Show answer

Answer: (d) 30%

IS 456 Cl. 37.1.1 permits redistribution of moments up to a maximum of 30% in limit state design.

Q23.Two footings, one circular and other square, are founded in pure clay. The diameter of the circular footing is the same as the side of the square footing. The ratio of their net ultimate bearing capacities is

  1. Near unity
  2. 1.3
  3. 1/1.3
  4. None of the above
Show answer

Answer: (a) Near unity

Skempton's bearing capacity factor Nc for square and circular footings in clay are very close (≈6.2), so the ratio of ultimate bearing capacities is nearly unity.

Q24.A raft of size 10 m x 10 m is founded at a depth of 5 m in a deposit of clay with undrained shear strength of 30 kN/m². With a factor of safety of 2.5, the net safe bearing capacity will be

  1. 86.3 kN/m²
  2. 79.2 kN/m²
  3. 93 kN/m²
  4. 97 kN/m²
Show answer

Answer: (b) 79.2 kN/m²

Using qnet(ult) = 5.14×Cu×shape and depth factors for the 10m×10m raft at 5m depth, and dividing by FS=2.5, gives a net safe bearing capacity close to 79.2 kN/m².

Q25.Group efficiency of a pile group

  1. Will always be less than 100%
  2. Will always be greater than 100%
  3. May be less than 100% or more than 100% depending upon the type of soil
  4. Is more than 100% for pile groups in cohesionless soils and less than 100% for pile groups in cohesive soils
Show answer

Answer: (c) May be less than 100% or more than 100% depending upon the type of soil

Pile group efficiency varies with soil type — it can exceed 100% in dense cohesionless soil (densification) or fall below it in cohesive soil (overlapping stress zones).

Q26.Length of a rectangular sedimentation tank should not be more than (B = width of tank)

  1. B
  2. 2B
  3. 4B
  4. 8B
Show answer

Answer: (c) 4B

Standard practice limits a rectangular sedimentation tank's length to about 4 times its width (L ≤ 4B) for even flow distribution.

Q27.Dissolved oxygen level in natural unpolluted waters at normal temperature is found to be of the order of

  1. 1 mg/L
  2. 10 mg/L
  3. 100 mg/L
  4. 1000 mg/L
Show answer

Answer: (b) 10 mg/L

Dissolved oxygen in natural, unpolluted water at normal temperature approaches saturation, on the order of 8-10 mg/L.

Q28.Product of H⁺ ions and OH⁻ ions in a stronger alkali is

  1. 0
  2. 1
  3. 10⁻¹
  4. 10⁻¹⁴
Show answer

Answer: (d) 10⁻¹⁴

The ionic product of water, Kw = [H+][OH-], is a constant equal to 10⁻¹⁴ at 25°C regardless of whether the solution is acidic or alkaline.

Q29.Turbidity is measured on

  1. Standard silica scale
  2. Standard cobalt scale
  3. Standard platinum scale
  4. Platinum cobalt scale
Show answer

Answer: (a) Standard silica scale

Turbidity is traditionally measured against a standard silica scale (e.g. Jackson Candle method); colour, not turbidity, uses the platinum-cobalt scale.

Q30.The most common cause of acidity in water is

  1. Carbon dioxide
  2. Oxygen
  3. Hydrogen
  4. Nitrogen
Show answer

Answer: (a) Carbon dioxide

Dissolved carbon dioxide forming carbonic acid is the most common natural cause of acidity in water.

Q31.Lacey's regime scour depth is given by (q = discharge per unit width, f = silt factor)

  1. 1.35(q/f)^(1/3)
  2. 1.35(q²/f)^(1/6)
  3. 1.35(q²/f)^(1/3)
  4. 1.35(q/f)^(1/6)
Show answer

Answer: (c) 1.35(q²/f)^(1/3)

Lacey's regime scour depth formula is R = 1.35 × (q²/f)^(1/3), where q is discharge per unit width and f is the silt factor.

Q32.In a siphon aqueduct, the most severe condition of uplift on the floor occurs when

  1. Canal runs full, drain is dry but the water table is at stream bed
  2. Canal is dry and drain is at high flood level
  3. Canal runs dry and drain also runs dry
  4. Both the canal and drain run full
Show answer

Answer: (b) Canal is dry and drain is at high flood level

Uplift on a siphon aqueduct's floor is worst when the canal (which normally loads the barrel from above) is empty while the drain outside is at high flood, maximising net upward pressure.

Q33.Duty is largest

  1. At the head of water course
  2. On the field
  3. At the head of main canal
  4. Same at all places
Show answer

Answer: (b) On the field

Duty is smallest at the head of the main canal (conveyance losses mean more water is needed there) and largest right on the field, where none of those losses remain to be accounted for.

Q34.Water utilizable by plants is available in soils mainly in the form of

  1. Gravity water
  2. Capillary water
  3. Hydroscopic water
  4. Chemical water
Show answer

Answer: (b) Capillary water

Capillary water, held by surface tension in the soil pores just above the water table, is the main form of moisture available for plant uptake.

Q35.According to Khosla's theory, the exit gradient in the absence of a downstream cutoff is

  1. 0
  2. Unity
  3. Infinity
  4. Very large
Show answer

Answer: (c) Infinity

Without a downstream cutoff, Khosla's theory shows the exit gradient at the toe mathematically approaches infinity, which is exactly why a cutoff is essential there.

Q36.A divide wall is provided

  1. At right angle to axis of weir
  2. Parallel to the axis of weir and upstream of it
  3. Parallel to the axis of weir and downstream of it
  4. At an inclination to the axis of weir
Show answer

Answer: (a) At right angle to axis of weir

A divide wall runs at right angles to the weir's axis, separating the weir bay from the under-sluice bay.

Q37.If the R.L's of canal bed level and high flood level of drainage are 212.0 m and 210.0 m respectively, then cross drainage work will be

  1. Aqueduct
  2. Super passage
  3. Siphon
  4. Siphon aqueduct
Show answer

Answer: (a) Aqueduct

Since the canal bed (212 m) is above the drain's high flood level (210 m), the canal can simply cross over the drain in a trough — an aqueduct.

Q38.Water stored in a reservoir below minimum pool level is called

  1. Useful storage
  2. Dead storage
  3. Valley storage
  4. Surcharge storage
Show answer

Answer: (b) Dead storage

Water held below the minimum drawdown (pool) level, unavailable for normal release, is called dead storage.

Q39.Horizontal distances obtained by tacheometric observations

  1. Require slope correction
  2. Require tension correction
  3. Require slope and tension correction
  4. Do not require slope and tension correction
Show answer

Answer: (d) Do not require slope and tension correction

Once reduced through the standard tacheometric formula (D = kS·cos²θ), the horizontal distance obtained doesn't need the further slope/tension corrections that taped measurements require.

Q40.The shape of a vertical curve generally provided is

  1. Circular
  2. Parabolic
  3. Spiral
  4. Elliptical
Show answer

Answer: (b) Parabolic

Vertical curves in road alignment are conventionally designed as simple parabolas for a smooth, easily-computed transition.

Q41.Major resisting force in a gravity dam is

  1. Water pressure
  2. Wave pressure
  3. Self weight of dam
  4. Uplift pressure
Show answer

Answer: (c) Self weight of dam

A gravity dam relies primarily on its own self-weight to resist overturning and sliding forces.

Q42.For the upstream face of an earthen dam most adverse condition for stability of slope is

  1. Sudden draw down
  2. Steady seepage
  3. During construction
  4. Sloughing of slope
Show answer

Answer: (a) Sudden draw down

Sudden drawdown removes the stabilising external water pressure on the upstream face while internal pore pressure hasn't yet dissipated — the most critical condition for that face.

Q43.Euler's formula states that the buckling load P for a column of length L, both ends hinged, whose least moment of inertia and modulus of elasticity of the material of the column are I and E respectively, is given by

  1. P = π²EI/L
  2. P = π²EI/L²
  3. P = πL²/EI
  4. P = πEI/L²
Show answer

Answer: (b) P = π²EI/L²

Euler's buckling load for a both-ends-hinged column is P = π²EI/L².

Q44.Maximum deflection of a simply supported beam of length L with a central concentrated load W is

  1. WL²/48EI
  2. WL²/24EI
  3. WL³/48EI
  4. WL²/8EI
Show answer

Answer: (c) WL³/48EI

Maximum deflection of a simply supported beam with a central point load W is WL³/48EI.

Q45.Maximum bending moment due to a moving load on a simply supported beam occurs

  1. at the mid-span
  2. at the supports
  3. under the load
  4. anywhere in the span
Show answer

Answer: (c) under the load

For a single moving point load on a simply supported beam, the absolute maximum bending moment occurs directly under the load (when it sits at midspan).

Q46.Portal bracing in truss bridge is used to

  1. Transfer load from top of end posts to bearings
  2. Keep the rectangular shape of the bridge cross-section
  3. Stiffen the structure laterally
  4. Prevent sideways buckling of top chord
Show answer

Answer: (a) Transfer load from top of end posts to bearings

Portal bracing carries the lateral (wind) load collected by the top lateral system down through the end posts to the bearings.

Q47.Efficiency of a riveted joint having minimum pitch as per IS:800 is

  1. 40%
  2. 50%
  3. 60%
  4. 70%
Show answer

Answer: (a) 40%

At minimum rivet pitch (holes closest together, most material removed per unit length), a simple riveted joint's efficiency is at its lowest — commonly worked out to around 40% in textbook examples.

Q48.Bolts are most suitable to carry

  1. Shear
  2. Bending
  3. Axial tension
  4. Shear and bending
Show answer

Answer: (a) Shear

Ordinary bolts are most efficient carrying shear; they're a poor choice for direct tension or bending due to thread stress concentration and prying action.

Q49.Slenderness ratio of lacing bars should not exceed

  1. 100
  2. 120
  3. 145
  4. 180
Show answer

Answer: (c) 145

IS 800 limits the slenderness ratio of lacing bars to 145.

Q50.A butt weld is specified by

  1. Effective throat thickness
  2. Plate thickness
  3. Size of weld
  4. Penetration thickness
Show answer

Answer: (a) Effective throat thickness

A butt weld's strength is governed by, and specified in terms of, its effective throat thickness.

Q51.Strain energy of a member may be equated to

  1. average resistance × displacement
  2. ½ × stress × strain × area of cross-section
  3. ½ × stress × strain × volume of member
  4. ½ × (stress)² × volume of member / Young's modulus
Show answer

Answer: (c) ½ × stress × strain × volume of member

Strain energy stored in an elastic member equals ½ × stress × strain × volume of the member.

Q52.Two standard angles 50×50×6 (ISA 5050) are placed back to back touching each other to form a column 3 m long. Assuming ends are hinged, E = 210 GN/m² and proportional limit stress 210 MN/m², the critical load will be

  1. 30 kN
  2. 40 kN
  3. 60 kN
  4. 80 kN
Show answer

Answer: (b) 40 kN

For the back-to-back ISA 50×50×6 column (L=3m, hinged-hinged), Euler's formula with the section's least moment of inertia gives a critical load of about 40 kN.

Q53.Most accurate method of finding the average depth of rainfall over an area is

  1. Isohyetal method
  2. Arithmetic mean method
  3. Thiessen polygon method
  4. Any of the above
Show answer

Answer: (a) Isohyetal method

The isohyetal method, which draws actual rainfall contours accounting for topography, is considered the most accurate way to find average rainfall over an area.

Q54.Gantry girders are designed to resist

  1. Lateral loads
  2. Longitudinal and vertical loads
  3. Lateral, longitudinal and vertical loads
  4. Lateral and longitudinal loads
Show answer

Answer: (c) Lateral, longitudinal and vertical loads

Gantry girders carry the crane's vertical wheel loads plus lateral surge and longitudinal (braking/traction) loads together.

Q55.As per IS code, the maximum bending moment for design of purlins can be taken as (W = total distributed load including wind load; L = centre-to-centre distance of supports)

  1. WL/6
  2. WL/8
  3. WL/10
  4. WL/12
Show answer

Answer: (c) WL/10

IS code practice takes the maximum design bending moment for continuous purlins as WL/10, less than the simple-span WL/8 due to continuity.

Q56.Lug angles

  1. Are used to reduce the length of connection
  2. Are unequal angles
  3. Increases shear lag
  4. All of the above
Show answer

Answer: (a) Are used to reduce the length of connection

A lug angle is added to an under-length connecting angle specifically to shorten the overall connection length needed.

Q57.Battens provided for a compression member shall be designed to carry a transverse shear equal to:

  1. 2.5% of axial force in member
  2. 5% of axial force in member
  3. 10% of axial force in member
  4. 20% of axial force in member
Show answer

Answer: (a) 2.5% of axial force in member

IS 800 requires both lacing and battens to be designed for a transverse shear of 2.5% of the axial force in the member.

Q58.Negative skin friction on piles may occur when

  1. Pile settlement is greater than soil settlement
  2. Soil settlement is greater than pile settlement
  3. Soil settlement is equal to pile settlement
  4. Soil settlement is half of pile settlement
Show answer

Answer: (b) Soil settlement is greater than pile settlement

Negative skin friction occurs when the surrounding soil settles more than the pile, dragging the pile down and adding load instead of resisting it.

Q59.Skin friction and end bearing resistance of piles can be obtained in a separated way by

  1. Routine pile load test
  2. Initial pile load test
  3. Cyclic pile load test
  4. None of these
Show answer

Answer: (c) Cyclic pile load test

A cyclic pile load test helps separate shaft friction (which mobilises fully early and doesn't grow further) from end bearing (which keeps developing) across repeated load cycles.

Q60.In case of 2-way slab, the limiting deflection is

  1. Primarily a function of long span
  2. Primarily a function of short span
  3. Independent of long or short span
  4. Dependent on both long and short span
Show answer

Answer: (b) Primarily a function of short span

In a two-way slab, deflection behaviour is governed primarily by the shorter span, which carries the greater share of the load.

Q61.Allowable deflection in reinforced concrete beams shall not exceed

  1. Span/250
  2. Span/300
  3. Span/350
  4. Span/400
Show answer

Answer: (a) Span/250

IS 456 sets the overall (including long-term/creep) allowable deflection limit for RC beams at span/250.

Q62.In limit state design of concrete structures strain distribution is assumed to be

  1. Linear
  2. Non-linear
  3. Parabolic
  4. Parabolic and rectangular
Show answer

Answer: (a) Linear

Strain distribution across a section is always assumed linear (plane sections remain plane); it's the stress block, not the strain, that's taken as parabolic-rectangular.

Q63.Reduction co-efficient of a reinforced concrete column with an effective length of 4.8 m and size 250x300 mm is

  1. 0.80
  2. 0.85
  3. 0.90
  4. 0.95
Show answer

Answer: (b) 0.85

With Leff=4.8m and least dimension D=250mm, IS 456's Cr = 1.25 - Leff/(48D) = 1.25 - 4800/12000 = 0.85.

Q64.Drops are provided in flat slab to resist

  1. Bending moment
  2. Thrust
  3. Shear
  4. Torsion
Show answer

Answer: (c) Shear

Drop panels near columns in a flat slab exist mainly to increase the section's capacity against punching shear.

Q65.If the loaded length of span in metres of a railway steel bridge carrying a single track is 6 m, the impact factor is taken as

  1. 0
  2. 0.5
  3. Between 0.5 and 1.0
  4. 1.0
Show answer

Answer: (c) Between 0.5 and 1.0

For a short loaded length like 6 m on a single-track steel railway bridge, the impact factor is high, falling in the range between 0.5 and 1.0.

Q66.A hill road is one which passes through a terrain with a cross slope of

  1. 0 to 10%
  2. 10 to 25%
  3. 25 to 60%
  4. none of the above
Show answer

Answer: (c) 25 to 60%

IRC terrain classification places cross slopes of 25-60% in the mountainous/hill category.

Q67.The camber for hill roads in case of bituminous surfacing is

  1. 2%
  2. 2.5%
  3. 3%
  4. 4%
Show answer

Answer: (c) 3%

Hill roads with bituminous surfacing are typically given a steeper camber (around 3%) than plain-terrain roads, for faster drainage.

Q68.The W-index will always be

  1. equal to the φ-index
  2. more than the φ-index
  3. less than the φ-index
  4. a constant fraction of the φ-index
Show answer

Answer: (c) less than the φ-index

W-index strips out initial losses separately, so it works out consistently lower than or equal to the average φ-index for the same storm.

Q69.An aquifer which is underlain by an impermeable layer at the bottom and not confined at the top is known as

  1. confined aquifer
  2. unconfined aquifer
  3. semiconfined aquifer
  4. perched aquifer
Show answer

Answer: (b) unconfined aquifer

An aquifer bounded below by an impermeable layer but open (unconfined) at the top, with a free water table, is an unconfined aquifer.

Q70.Water existing in capillary zone is a part of

  1. phreatic water
  2. ground water
  3. gravity water
  4. vadose water
Show answer

Answer: (d) vadose water

Capillary water sits within the vadose (unsaturated) zone, above the water table.

Q71.Disinfection of water results in

  1. Removal of turbidity
  2. Removal of hardness
  3. Killing of disease bacteria
  4. Complete sterilisation
Show answer

Answer: (c) Killing of disease bacteria

The main purpose of disinfecting water is to kill disease-causing pathogens — not to sterilise it completely or remove turbidity/hardness.

Q72.Period of cleaning of slow sand filters is about

  1. 24-48 hrs
  2. 10-12 days
  3. 2-3 months
  4. 1-2 year
Show answer

Answer: (c) 2-3 months

Slow sand filters run for extended periods before the clogged schmutzdecke layer needs scraping — typically every 2-3 months.

Q73.Pathogens can be killed by

  1. Nitrification
  2. Chlorination
  3. Oxidation
  4. None of the above
Show answer

Answer: (b) Chlorination

Chlorination is the standard method used specifically to kill pathogens in water treatment.

Q74.If BOD of a town is 20000 kg/day and BoD per capita per day is 0.05 Kg, then population equivalent of town is

  1. 1000
  2. 4000
  3. 100000
  4. 400000
Show answer

Answer: (d) 400000

Population equivalent = total BOD load ÷ per-capita BOD = 20000 ÷ 0.05 = 400,000.

Q75.For normal sludge, the value of sludge index for Indian conditions is

  1. 0 to 50
  2. 50 to 150
  3. 150 to 350
  4. 350 to 500
Show answer

Answer: (b) 50 to 150

A sludge volume index of roughly 50-150 is considered normal, well-settling sludge under Indian conditions.

Q76.In a single-point method of finding mean velocity across a vertical, the velocity is measured above the stream bed at a depth (d) of

  1. 0.4d
  2. 0.6d
  3. 0.7d
  4. 0.8d
Show answer

Answer: (b) 0.6d

The single-point method for mean velocity in a vertical takes the reading at 0.6 times the depth below the surface.

Q77.If N is the speed of a current meter in revolutions per second, the velocity measured by it is proportional to

  1. N¹ᐟ²
  2. N
  3. N³ᐟ²
  4. N²
Show answer

Answer: (b) N

The standard current-meter rating equation (V = aN + b) makes velocity approximately directly proportional to the rotation speed N.

Q78.Maximum width of a vehicle recommended by IRC is

  1. 1.85 m
  2. 2.44 m
  3. 3.81 m
  4. 4.72 m
Show answer

Answer: (b) 2.44 m

IRC recommends a maximum vehicle width of 2.44 m on Indian roads.

Q79.Stopping sight distance is always

  1. less than overtaking sight distance
  2. equal to overtaking sight distance
  3. more than overtaking sight distance
  4. none of the above
Show answer

Answer: (a) less than overtaking sight distance

Stopping sight distance is always shorter than overtaking sight distance, since overtaking needs room to accelerate past another vehicle and return safely.

Q80.Toughness index is the ratio of

  1. consistency index to flow index
  2. flow index to plasticity index
  3. liquidity index to flow index
  4. plasticity index to flow index
Show answer

Answer: (d) plasticity index to flow index

Toughness index is defined as the ratio of plasticity index to flow index (It = Ip/If).

Q81.A sample of clay has a natural water content of 64%. Its liquid limit was found to be 75% and plastic limit 35%. Its liquidity index will be

  1. 45.6%
  2. 72.5%
  3. 56.8%
  4. 64%
Show answer

Answer: (b) 72.5%

Liquidity index = (w - PL)/(LL - PL) = (64-35)/(75-35) = 29/40 = 72.5%.

Q82.Time factor for a particular average degree of consolidation

  1. always depends upon the distribution of initial excess hydrostatic pressure with depth
  2. depends upon the co-efficient of consolidation
  3. depends upon the drainage path
  4. is independent of the distribution of initial excess hydrostatic pressure
Show answer

Answer: (a) always depends upon the distribution of initial excess hydrostatic pressure with depth

The standard time factor-degree of consolidation relationship is derived assuming a particular initial excess pore pressure distribution with depth, so it depends on that distribution.

Q83.A clay deposit suffers a total settlement of 5 cm with one-way drainage. With two-way drainage the total settlement will be

  1. 10 cm
  2. 2.5 cm
  3. 20 cm
  4. 5 cm
Show answer

Answer: (d) 5 cm

Total (ultimate) consolidation settlement depends on the load and soil compressibility, not on the number of drainage faces — two-way drainage only makes it happen faster, not larger; it stays 5 cm.

Q84.The nearest object from a raingauge should be at a minimum distance equal to

  1. Its height
  2. Twice its height
  3. Thrice its height
  4. Four times its height
Show answer

Answer: (b) Twice its height

Standard practice keeps obstructions at least twice their own height away from a raingauge, so they don't shield it from rainfall.

Q85.Any cyclic trend present in rainfall data can be ascertained from

  1. depth-area duration curve
  2. moving average curve
  3. intensity-duration curve
  4. double mass curve
Show answer

Answer: (b) moving average curve

A moving average curve smooths short-term scatter in rainfall records, making any underlying cyclic trend easier to see.

Q86.Rates of rainfall for half-hour periods of a 3 hr storm are 1.6, 3.6, 5.0, 2.8, 2.2, 1.0 cm/hr. The corresponding surface run-off is estimated at 3.6 cm. The φ-index will be

  1. 1.6 cm/hr
  2. 2.4 cm/hr
  3. 2.0 cm/hr
  4. 3.2 cm/hr
Show answer

Answer: (a) 1.6 cm/hr

Testing φ=1.6 cm/hr: excess rainfall over the periods exceeding it sums to exactly 3.6 cm, matching the given runoff — so φ-index = 1.6 cm/hr.

Q87.Maximum average rainfall intensity at a given location

  1. Increases with increase in duration
  2. Decreases with increase in duration
  3. Independent of duration of rainfall
  4. Sometimes increases and sometimes decreases with increase in duration
Show answer

Answer: (b) Decreases with increase in duration

Rainfall intensity-duration relationships always show average intensity decreasing as the duration considered gets longer.

Q88.In the quadrantal bearing system, a whole-circle bearing of 293°30' can be expressed as

  1. W23°30'N
  2. N66°30'W
  3. S113°30'N
  4. N23°30'W
Show answer

Answer: (b) N66°30'W

A whole-circle bearing of 293°30' falls in the NW quadrant; reduced bearing = N(360°-293°30')W = N66°30'W.

Q89.Adjustment of horizontal cross hair is required particularly when the instrument is used, for

  1. Levelling
  2. Prolonging a straight line
  3. Measurement of horizontal angles
  4. All of the above
Show answer

Answer: (a) Levelling

An out-of-adjustment horizontal cross-hair directly biases staff readings, so its correct adjustment matters most for levelling work.

Q90.Following sights are taken on a 'turning point'

  1. Foresight only
  2. Backsight only
  3. Foresight and Backsight
  4. Foresight and Intermediate sight
Show answer

Answer: (c) Foresight and Backsight

A turning point is where a foresight closes one instrument setup and a backsight opens the next — both are taken there.

Q91.Rise and Fall method of levelling provides a complete check on

  1. Backsight
  2. Intermediate sight
  3. Foresight
  4. All of the above
Show answer

Answer: (d) All of the above

The Rise and Fall method checks every reading taken (backsight, intermediate sight and foresight alike), unlike the Height of Instrument method.

Q92.Size of a plane table is

  1. 750 mm x 900 mm
  2. 600 mm x 750 mm
  3. 450 mm x 600 mm
  4. 300 mm x 450 mm
Show answer

Answer: (b) 600 mm x 750 mm

A standard plane table is commonly cited as 750mm × 600mm (drawing board size).

Q93.Composting and lagooning are the methods of

  1. Sludge digestion
  2. Sludge disposal
  3. Sedimentation
  4. Filtration
Show answer

Answer: (b) Sludge disposal

Composting and lagooning are methods used for final disposal of treated sludge.

Q94.Width of ballast section for Broad Gauge is

  1. 1.83 m
  2. 2.25m
  3. 3.35m
  4. 4.30 m
Show answer

Answer: (c) 3.35m

Standard ballast section width for Broad Gauge formation is about 3.35 m.

Q95.Composite sleeper index is the index of

  1. Hardness and strength
  2. Strength and toughness
  3. Toughness and weir resistance
  4. Wear resistance and Hardness
Show answer

Answer: (d) Wear resistance and Hardness

Composite sleeper index combines a timber's wear resistance and hardness into one rating.

Q96.Normal maximum cant permissible in Metre Gauge is

  1. 75 mm
  2. 90 mm
  3. 140mm
  4. 165 mm
Show answer

Answer: (b) 90 mm

Maximum permissible cant on Metre Gauge track is 90 mm (lower than Broad Gauge's 165 mm).

Q97.A series of closely spaced contour lines represents a

  1. Steep slope
  2. Gentle slope
  3. Uniform slope
  4. Plane surface
Show answer

Answer: (a) Steep slope

Closely spaced contour lines indicate rapid elevation change over a short distance — a steep slope.

Q98.The instrument used for accurate centering in plane table survey is

  1. Spirit level
  2. Alidade
  3. Plumbing fork
  4. Trough compass
Show answer

Answer: (c) Plumbing fork

A plumbing fork with a plumb bob is the instrument specifically used to centre a plane table accurately over a ground station.

Q99.Two point problem and three point problem are methods of

  1. resection
  2. orientation
  3. traversing
  4. resection and orientation
Show answer

Answer: (a) resection

The two-point and three-point problems are both classic plane-table resection techniques.

Q100.Bowditch rule is applied to

  1. An open traverse for graphical adjustment
  2. A closed traverse for adjustment of closing error
  3. Determining the effect of local attraction
  4. None of the above
Show answer

Answer: (b) A closed traverse for adjustment of closing error

Bowditch's rule distributes a closed traverse's closing error across all the legs in proportion to their length.

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