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All 98 questions from the WBPSC AE 1998 (Public Works Department) paper (1998 — Public Works Department). Answers and explanations for the first 10 are free below; the rest are in the full previous-papers pack, along with timed practice and scoring.
| Paper | 1998 — Public Works Department |
| Questions | 98 |
| Marking (current pattern) | +2 for a right answer, −2/3 for a wrong one |
| Answers on this page | Q1–Q10 (rest in the full pack) |
Q1.If a two hinged parabolic arch of span L and rise h is subjected to u.d.l. of intensity W over half of its span, the horizontal thrust at the supports is equal to
Answer: (d) WL²/16h
A two-hinged parabolic arch carrying a UDL over the whole span develops the classical thrust H = wL²/8h. The load here covers only half the span, and thrust is a linear function of the load, so superposition settles the question at once. Load the left half alone (thrust H1) and the right half alone (thrust H2). Together they reproduce the full-span UDL, and by symmetry H1 = H2.
Q2.The free end b of a cantilever beam AB of length L is found to deflect too much and is jacked up to the same level as A. If the beam carries a uniformly distributed load W per unit length, what will be the force on the jack?
Answer: (b) 3/8 WL
The jack converts the propped condition into a compatibility problem: the net deflection of the free end B is zero. Superpose the downward deflection caused by the UDL on the free cantilever with the upward deflection caused by the jack force P. δUDL = wL⁴/8EI (downwards), δP = PL³/3EI (upwards) Equating them gives P = 3wL/8. This is precisely the reaction at the prop of a propped cantilever, which is why 3wL/8 and its partner 5wL/8 at the fixed end are worth memorising.
Q3.A beam of span L is fixed at both ends and carries two loads each P, at a distance L/4 from each end. It is found that the resulting deflection produced at the centre of the span is Δ. If one load, equal to 2P, acts at the centre of span, what deflection will be produced at each quarter span point?
Answer: (c) Δ
This is a direct application of Maxwell's reciprocal theorem: the deflection at point 1 due to a unit load at point 2 equals the deflection at point 2 due to a unit load at 1, provided the structure is linearly elastic. Call that common flexibility coefficient f (quarter point ↔ centre). Case 1 — loads P at L/4 and at 3L/4. By symmetry each contributes Pf at the centre, so Δ = 2Pf, giving f = Δ/2P. Case 2 — a single load 2P at the centre.
Q4.A beam of span L is fixed at both ends and carries a point load W at its mid-span point. At what distance from each support will be the points of contraflexure?
Answer: (b) L/4
For a beam fixed at both ends with a central point load W, the fixed-end moments are WL/8 (hogging) and the mid-span moment is +WL/8 (sagging). The bending moment varies linearly from support to mid-span, so it crosses zero exactly halfway between them.
Q5.A fixed end beam AB of span L has hinges at distances L/4 from either end. If the beam carries a uniformly distributed load of w per unit length, what will be the maximum B.M. in it?
Answer: (b) 3WL²/32
Two internal hinges release two redundancies, so the beam becomes statically determinate. Read it as three pieces: a simply supported span BC of length L/2 resting on the hinges, and two cantilevers of length L/4 projecting from the fixed ends and carrying the hinge reactions. Middle span (length L/2, UDL w): hinge reaction = w(L/2)/2 = wL/4; mid-span sagging moment = w(L/2)²/8 = wL²/32. Cantilever (length L/4): carries its own UDL plus the hinge reaction at its tip.
Q6.The ends A and B of member 5m long, are subjected to unequal sagging moments MA greater than MB, without allowing any change in the level of supports. If MA is 50 T-m and MB is [value not clearly legible in scan] T-m, what are the support reactions?
Answer: (a) RA = 14T upwards, RB = 14T downwards
Between the two ends there is no transverse load, only the applied end moments. Vertical equilibrium then forces the two reactions to be equal in magnitude and opposite in direction — they form a couple. That single observation eliminates the two options showing both reactions acting the same way.
Q7.A beam ABCD is built in at the end supports A and D and is provided with two hinges at B and C where AB=CD=L and BC=2L. What minimum part of the beam should be covered by a uniformly distributed load to produce maximum bending moment at A?
Answer: (b) AC (or BD)
Hinges at B and C make the beam determinate. Cut it there and the load path becomes obvious: Span BC (length 2L) is a simply supported beam sitting on the two hinges. AB is a cantilever fixed at A; CD is a cantilever fixed at D. Load on AB acts directly on the A-cantilever. Load on BC delivers half its total as a downward reaction at hinge B, which lands on the tip of the A-cantilever — again hogging at A.
Q8.Applied load vector premultiplied by inverse of stiffness matrix is equal to
Answer: (b) Displacement vector
The stiffness (displacement) method is written as [K]{Δ} = {P} ⟹ {Δ} = [K]−1{P} Pre-multiplying the load vector by the inverse of the stiffness matrix therefore returns the displacement vector. The inverse of the stiffness matrix is by definition the flexibility matrix [F] = [K]−1, but the product [F]{P} is a vector of displacements, not a matrix. Reading the units confirms it: stiffness is force/length, so its inverse is length/force, and (length/force) × force = length.
Q9.At a plastic hinge
Answer: (d) The B.M is equal to the fully plastic moment of the section
A plastic hinge forms when the whole section has yielded — the stress block becomes two rectangles at fy, one in compression and one in tension. The moment carried at that state is the fully plastic moment Mp = fy Zp, where Zp is the plastic section modulus The hinge then rotates freely at constant moment Mp. It is not a real hinge: a real hinge transmits zero moment, whereas a plastic hinge transmits Mp throughout the rotation.
Q10.What is the degree of redundancy of a rigid building frame consisting of two bays, one of which is three-storied and the other two stories and all the three column bases being fixed?
Answer: (c) 15
For a rigid-jointed plane frame with fixed bases and no internal hinges, the degree of static indeterminacy equals 3 × (number of closed boxes). Two bays means three columns. The first bay is three storeys high (3 panels) and the second is two storeys high (2 panels), so the frame encloses 5 closed panels: Ds = 3 × 5 = 15 The member–joint count confirms it. Columns: 3 + 3 + 2 = 8 segments; beams: 3 + 2 = 5; so m = 13. Joints including supports: j = 11.
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Unlock all 12 papers — Rs. 349Q11.A simply supported uniform beam ABC overhangs beyonds B to C, such that AB=L and BC=L/3. If it is to carry factored verical loads of 2W at mid-span of AB and W at the free end C, what is the value of Mp that should be provided?
Q12.In the collapse load method of designing a structure the collapse is said to take place when
Q13.For simply supported beam the maximum ordinate of influence line for bending moment at one-third span is
Q14.The degree of statical indeterminancy for a pin jointed space frame is given by the following, where m = number of members, J = total number of joints including the supprots, r = number of reaction components:
Q15.In a statically indeterminate structure, the redundants must be such as to make the total strain energy a minimum. The statement is the deifinition of:
Q16.Weakest section in a fillet weld is
Q17.The strength of the welded joint
Q18.Ratio of permissible bearing stress in power drirver field rivets with respect to that for shop rivet is
Q19.Maximum permissible longitudinal pitch of rivets in rivett joints in compression momoers, is
Q20.Maximum permissible slenderness ration for a tie member in a roof truss is
Q21.Diameter of a rivet hole for rivet diameter less than 25 mm is usually considered as
Q22.Transverse surge force on the rail head from on EOT crane girder, when compared with combined wieght of crab and weight lifted is
Q23.Intermediate vertical stiffeners are provided in a plate girder if the web plate thickness is less than
Q24.In a steel roof truss, s tension member consists of single angle connected by rivets to gueset plates, cross sectional area to be considered for design is
Q25.When effect of wind or earthquake load is taken into account the permissible stresses on rivets, bolts and tension rods may be exceeded by
Q26.Maximum permitted slenderness ratio for a structural member carrying compressive load due to D.L. and L.L. is
Q27.Slenderness ratio of the lacing bars for compression members shall not exceed
Q28.Projection of a plate or flange in tension, beyond its connected to a web, or other line of support shall not exceed
Q29.Impact allowance for crane girders and supporting coloumns for electrically operated heavy duty cranes is
Q30.Cross-sectional area being the same, the most economical section for a column is
Q31.For single lacingbars, the thickness of flat bracing bare shall not be less than
Q32.The allowable tensile stress in mild steel stirrups in R.C. structure (working stress method) is
Q33.In the working stress method of R.C. design, permissible bending compressive stress in concrete is approximately equal to
Q34.Development length of a rainforcing bar
Q35.For the design of R.C. columns a column is treated as short one if the ratio of effective length to its least lateral dimension is less than
Q36.In the limit state method of R.C. design, maximum permissible compressive strain concrete is
Q37.Minimum percentage of high yield deformed bars in R.C. slab compared with gross concrete area is
Q38.The minimum diameter of longitudinal bars in a R.C. column is
Q39.To take care of reversible shear in an R.C.C. beam, it is advisable to use
Q40.In prestressed concreto construction high tensile steel is used for prestressing because
Q41.For a 90° bend in rein forcement, anchorage value is kd where d = diameter of rainforcement and the value of k is
Q42.A decrease in stress at constant strain in called
Q43.Steel is used as reinforcement instead of other metals in reinforced concrete because
Q44.Reinforcement in a R.C.C column should be as follows
Q45.For footings on piles the thickness of concrete tops of piles shall not be less than
Q46.Critical section for shear in case of R.C.C beams in frame buildings is taken at a distance of
Q47.Howrah bridge (Rabindra setu) is a
Q48.Limiting moment of resistance for singly reinforced rectangular beams using Fe.415 steel is (usual notation being used)
Q49.The maximum area of tensile reinforcement in R.C.C beams shall not exceed
Q50.A R.C.C. column can be considered as a short column, if its slenderness ration is less than
Q51.For soil smapling, boreholes should be stabilised for
Q52.Sand piles are primarily used for
Q53.Standard split spoon sampler is used for
Q54.The pile tip and shaft resistances can be assessed separately from load test by
Q55.Immediate settlement of a shallow foundation in a clavey soil occurs due to
Q56.Two footing A (2m×2m) and B (4m×4m) are placed on a saturated conesive soil and Subjected to the same intensity of pressure. The immediate settlement of B will be
Q57.Negative skin friction develope in a pile when
Q58.'Sensitivity' of soil can be assessed from
Q59.In an unconfined compression test the specimen fails at a compressive stress of 14t/m². The shear strength of the soil is
Q60.Rankine's earth pressure theory is least violated in
Q61.Coeficient of earth pressure at rest is generally less than 1. But it can be greater than 1, if the soil is
Q62.Buoyant unit weight of soil is equal to sturated density
Q63.Passive earth pressure decreases with
Q64.Sheet piles are used primarily for
Q65.Intensity of active earth pressur at a depth of 10 in dry cohensionless soil with an angle of internal friction of 30 and with unit weight of 1.80 t/m³
Q66.Active earth pressure of a soil is proportionate to (θ = angle of internal friction of the soil)
Q67.Ratio of volume of voids to the total volume of the given soil mass is known as its
Q68.Net effective waterway under a bridge is calculated as follows:
Q69.In alluvial streams the well foundation for bridge piers shall have a grip length
Q70.Regime scour depth, R, for alluvial rivers is given by the following empirical formula due to lacey:
Q71.Softening point of a straight run-bitumen is etermined by
Q72.Softening point of a straight-run-bitumen is etermined by
Q73.In laboratory CBR is usually selected at
Q74.For road repair work at exceptionally cold weather condition at high altitude, which binder can be used most effectively?
Q75.Limestone dust filler material is required for production of
Q76.The maximum number of vehicles that can move on a road at any section during one hour under prevailing situation is known as
Q77."Marshall" stability is to be considered for design of
Q78.For non-cohesive materials compaction can be best achieved by
Q79.'Bankel man Beam' is used for
Q80.If R be the radius of main curve and L the length of the transition curve, the shift of the curve is
Q81.If the difference in elevation between the crown and the edge of the pavement of 9 m. width is 15 cm, the camber is
Q82.The formation width of a road means the width of
Q83.If V be the speed of a moving vehicle in m/sec r the radius of the curve in m, g the acceleration due to gravity in m/sec² and W the width of the carriageway in m, the raising of outer edge of pavement is
Q84.The steepest gradiet permitted on rads, which in ordinary conditions, is not exceeded is known as
Q85.The correct formula for calculating super-elevation for the hill roads is
Q86.To determine the overtaking sight distance the driver's eye height above road surface is considered to be
Q87.Bitumen stabilization is suitable for
Q88.In rotary intersection the weaving length is
Q89.Warping of concerete pavment cause
Q90.When the speed of traffic flow becomes zero, then
Q91.Grade compensation on hill road means
Q92.The dowel bars are used in rigid pavment
Q93.Tack coat is provided
Q94.While conducting traffic survey of a road, the composition of various vehicles are found to be (i) car-100 (ii) Bus-20, (iii) Truck-40. The P.C.U. of the road as per I.R.C. equivalency factors is
Q95.The term 'Vehicle Damage Factor' is
Q96.Maximum value of super relevation in plain terrain in urban road is
Q97.In winter during mid-day critical combination of stress at the edge of concreate pavment is
Q98.If L be the length of wheel base of a moving vehicle and R the radius of a curve, the mechanical widening per lane to be provided on the curve is
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