PSC Exam › Exam guides › WBPSC AE (Civil) › Previous papers
All 98 questions from the WBPSC AE Civil 2001 paper (Assistant Civil Engineer — 2001). Answers and explanations for the first 10 are free below; the rest are in the full previous-papers pack, along with timed practice and scoring.
| Paper | Assistant Civil Engineer — 2001 |
| Questions | 98 |
| Marking (current pattern) | +2 for a right answer, −2/3 for a wrong one |
| Answers on this page | Q1–Q10 (rest in the full pack) |
Q1.In case of mild steel, the value of the stress at elastic limit is
Answer: (b) More than that at limit of proportionality
On the tensile stress–strain curve of mild steel the first landmark is the limit of proportionality, the highest stress up to which σ ∝ ε and Hooke's law holds. A little beyond it lies the elastic limit — the highest stress from which the bar still returns to its original length on unloading. Between the two the curve has begun to bend, so the material is no longer linear, but it is still elastic: strain is fully recoverable.
Q2.The principal stresses at a point are 600 and 400 kg/cm² respectively, both tensile. The magnitude of normal and tangential stresses inclined at 45° to the plane on which the normal stress is 600 kg/cm² are respectively.
Answer: (d) 500 and 100 kg/cm²
With σ1 = 600 and σ2 = 400 kg/cm² (both tensile, no shear on the principal planes), the stresses on a plane whose normal is inclined at θ to the direction of σ1 are σn = (σ1+σ2)/2 + (σ1−σ2)/2 · cos2θ, τ = (σ1−σ2)/2 · sin2θ At θ = 45° the cosine term vanishes and the sine term is a maximum: the normal stress drops to the mean of the two principal stresses while the shear stress reaches its greatest value, the radius of the Mohr circle.
Q3.Point of contra-flexure is the point where
Answer: (c) The B.M. Charges sign
The point of contraflexure (or inflexion) is where the beam changes its curvature — the deflected shape turns from sagging to hogging. Since curvature is proportional to bending moment (M = EI·d²y/dx²), that is exactly the section at which the bending moment changes sign.
Q4.A cantilever beam of leangth 'l' is loaded with a u.d.l. of w' per unit length over a length of 'a' form the fixed end. The slop and deflection at the free end are respectively.
Answer: (a) wa³/6EI and wa⁴/8EI + wa³(L-a)/EI
Only the loaded length a from the fixed end bends; the remaining (l−a) of the cantilever carries no bending moment, so it stays straight and simply rotates rigidly about the end of the loaded portion. Treat the loaded part as a cantilever of length a with UDL w: θa = wa³/6EI , ya = wa⁴/8EI Beyond that section the slope cannot change, so the slope at the free end is the same wa³/6EI.
Q5.A compression member tends to buckle in the direction of
Answer: (d) Least radius of gyration
Euler's crippling load is Pcr = π²EI/le². Writing I = Ar² gives Pcr = π²EA/(le/r)², so the strut fails about whichever axis makes the slenderness ratio le/r largest. With the same effective length about both axes, that is the axis of least radius of gyration — and the column buckles in the plane perpendicular to that axis.
Q6.[Refers to Fig.1: a symmetric triangular/lattice truss with vertical loads 1000N, 2000N, 2000N, 1000N applied, supports at both ends] The force in the member AB of the loaded truss shown in Fig. 1, is
Answer: (d) 60000 N (compressive)
The truss is symmetrical and the loading (1000 + 2000 + 2000 + 1000 = 6000 N) is symmetrical, so each support carries 3000 N. AB is the end raker springing from the support. Take the free body of joint A: only the reaction, the raker AB and the horizontal bottom chord meet there.
Q7.A moving load of uniform filtensity w is spread over a length longer than the span L of a beam AB simply supported at the ends, when the tail of the load moving left to right reaches the point P, the maximum shear force at P is
Answer: (c) W(L-X)²/2L
For a UDL longer than the span, the shear at a section P (distance x from A) is greatest when the load occupies one side only of P. With the tail of the load just reaching P as the load travels left to right, the load covers P to B, a length (L−x), and the shear at P equals the reaction at A.
Q8.A beam AB of length 10 m having both ends fixed is acted upon by a concentrated load of 10 tonnes at C at a distance of 4m from A on the beam. The B.M. at C is
Answer: (a) Sagging and of magnitude 11.52 t.m
For a fixed beam with a point load W at distance a from A and b from B, the fixed-end moments are MA = Wab²/L² , MB = Wa²b/L² The bending moment under the load is the free (simply supported) moment Wab/L reduced by the fixing-moment ordinate read at C from the straight line joining MA and MB. Because the free moment is the larger, the net moment at C is sagging.
Q9.[Refers to Fig.2: a portal frame ABCD, EI=constant, member lengths marked 4m] In the portal frame shown in Fig. 2, the end A is fixed and D is hinged. The distribution factors at C are in the ratio of
Answer: (d) 0.57 : 0.43
Distribution factors are proportional to the rotational stiffness k of each member meeting at the joint. At C two members frame in — beam CB and column CD: CB has its far end B connected to the rest of the rigid frame, so use the full stiffness k = 4EI/L. CD has its far end D hinged, so use the reduced stiffness k = 3EI/L. With EI constant and both members 4 m long the relative stiffnesses are 4 and 3.
Q10.[Refers to Fig.3: an overhanging beam] The slope at the support and of the overhanging beam shown in Fig. 3 is given by
Answer: (b) Wl²/24EI
The overhang carries no load, so it contributes no bending moment to the span: the portion between the supports behaves exactly as a simply supported beam under its uniformly distributed load, and the unloaded overhang simply follows the tangent at the support. For a simply supported span l with UDL w per unit length the end slope is wl³/24EI.
Unlock all 12 WBPSC AE previous papers — 1,182 questions with answers, explanations and timed, scored practice. One payment, works on any device after you sign in.
Unlock all 12 papers — Rs. 349Q11.A 10 mm thick plate is connected with 12 mm thick plate by 5 mm fillet weld. Allowing permissible shear stress of 101 MPa in the weld, strength of weld p mm length is
Q12.Horizontal stiffness are generally provided when the ratio of clear depth to the thickness of web exceeds
Q13.Lug angles are
Q14.Difficulty in finishing of concrete surface is experienced when the slump of concrete exceeds
Q15.The overall depth of a wall footing is 560 mm and effective depth is 500 mm. The width of the footing is 3000 mm. The spacing of 10 mm bars for longitudinal reinforcemtn is
Q16.The spacings of counterforts depends on
Q17.Post tensioning is common in structures like
Q18.Characteristic load means that value of the load
Q19.The effective depth of a T beam for heavy loads is taken as
Q20.In the active state of plastic equilibrium behind a retaining wall the wall
Q21.If is the single of slope with the horizontal, and φ angle of shearing resistance, F, the factor of safety against sliding for a mass of soil bounded by a sloping surface is given by
Q22.Negative skin friction on pile may occur when
Q23.The intensity of vertical pressure at a depth Z directly below a varticll point load, P, is given by
Q24.The maximum settlement of raft foundation on sand should be limited to the following values:
Q25.The minimum gradient that is to be provided on a road is
Q26.The absolute minimum radius of horizontal curve is
Q27.The compensated gradient on a horizontal curve of 100 m radius, if the rulling gradient orovided on the road is 4% is
Q28.The total reaction time for an average dirver for normal situation is
Q29.The grain-size distribution of filter material for highway drainage is based on piping ratio
Q30.The nominal size of modular bricks is
Q31.Rapid hardening portland cement contains
Q32.Anti-siphonage pipe is used to
Q33.Critical path is PERT network is the one for which
Q34.A semi-circular arch is 30 cm thick, 60 cm wide and has a span of 2m. The quantity of arch-mascnry is
Q35.The megmetic bearing of a line AB is S28°E. If the declination at the location is 8° west, the true bearing of the line AB will be
Q36.In a 4m levelling staff, the thickness of the graduation of the scale
Q37.In the stadia method of techemetric surveying, the horizontal distance D, form the vertical axis of the instrument to the staff station is given by (When K1 and K2 appropriate e constants and S is he staff intercept)
Q38.A soil sample has a porosity of 40%. The specific gravity of solid particles is 2.70. The dry density of the soil will be
Q39.Identify the maximum uniformly graded soil from the uniformity coefficients of the soils given below:
Q40.For a coarses and with void ratio of 0.68 and specific gravity of soil solids of 2.68, critical hydraulic gradient will be
Q41.The optimum moisture content of a soil is 17%. Its specific gravity is 2.68. The theoretical maximum dry density of the soil corresponding zero air voids at optimum water content is
Q42.A flow is steady if (V=Velocity, P=Pressure, O=density and T and t are respectively Thermodynamic temperature and time)
Q43.In an enclosed flow of a liquid having no free surface, if p is the intensity of pressure at a point in the field, Z, the elevation of the point over an arbitrarily chosen datum v, the velocity of flow, γ, the specific weight, the piezometirc head, h is equal to
Q44.Flow of water in a pipe of diameter 3000 mm can be measured by
Q45.A pelton wheel is
Q46.Mixed cropping is eliminated, where
Q47.Consumptive Irrigation Requirement (CIR), if Cu consumptive use and Rs, the effective and Rs, the effective rainfal is given be
Q48.A crop that takes more than 4 months to mature is called
Q49.Average delta of a rice crop is mearly
Q50.The delta for a crop when its duty is 864 hectares/cumecs in the field, the base peirod being 120 days, is
Q51.Isohyets are
Q52.A hydrograph is a plot of
Q53.A self recording rain gauge
Q54.Run off is measured in
Q55.A channel is said to be in a state of true reigme, if the flow is such that there is
Q56.Where seepage loss is as high as 50% the earthen surface of the channel should be lined with
Q57.Fluming of the canal in cross drainage works means
Q58.A diversion head work is constructed to
Q59.Hydraulic jump occurs when a steep channel slope
Q60.A protection work at the downsteam and of ta weir in form of blocks of concrete or mesonry is called
Q61.Dams used to raise the river water level to feed on offtaking canal is called.
Q62.In case of a gravity dam, the main overturning force is
Q63.The best type of structures for dams to resist earthquake shocks
Q64.The value of acceleration due to earthquake in terms of 'g' the acceleration due to gravity, in ectremely scismic regions for design of gravity dams is equal to
Q65.The river training work for the primary purpose of flood control is called
Q66.If L is the length between the abuments, the minimum length of the upstream part of the guide bank is
Q67.A facing of dry stone pitching laid on sloping face of earth to maintain the slope in position or to protect it from erosion, is called.
Q68.In areas likely to be water-logged, the prefer able type of irrigation is
Q69.Removal of soluble salts by downward movement of water through the soil is called
Q70.Water logging leads to
Q71.If waste water has a phovalue of 6.5, it means that
Q72.As per norms 45 litres of water per person per day is provided in case of
Q73.In waste water, the solids which and decomposed, are
Q74.The source of surface water for supply to a community may be
Q75.The trap efficiency of a reservoir depends on the
Q76.Specific yield of a well is
Q77.In case of potable water, the permissible upper limit or chloride contents is
Q78.The permissible limit of arsenic concentration in domestic water supplies is
Q79.One of the usual parameters of pollution in domestic waste water is
Q80.Normal pH values in domestic waste water vary from
Q81.Activated carbon removes from water
Q82.Which of the following is the best coagulant for removing colour?
Q83.Which one of the following is the first stage in the treatment of water?
Q84.Slow sand filters remove bacteria as much as
Q85.The suitable layout of a distribution system for irregularly growing town is
Q86.The method which is most widely used for analysing and designing he pipes of all types of complex water distribution network is
Q87.The type of value which is provided to regulate the flow of after through the pipelines is
Q88.A.G.I pipe has a coating of
Q89.The function of gully trap is to
Q90.Self cleansing valocity in sever is racchieved by
Q91.The area of oxidation ponds is determined on the basis of the following approximate rule:
Q92.The oxygen sag curve exhibits an important dharacteristic given by a point on the curve indicating
Q93.The rate of deoxygenation LD in a river may be expressed as
Q94.A hand pump is a type of
Q95.The size of centrifugal water pump is given by
Q96.Major source of carbon monoxide pollution is
Q97.Cyclones are used for cleaning air by separation of
Q98.In a town, garbade is produced at the rate of
All 12 papers, every answer explained, timed and scored like the real exam.
Unlock all 12 papers — Rs. 34912 subjects, 20 MCQs each, scored instantly with explanations. Good for daily topic-wise revision.
Pick a subject ›1 set free100 questions on the RCC code, each answered with the exact IS 456 clause.
Start the free set ›2 subjects free2,604 recall questions across 26 subjects — quick revision of the whole technical syllabus.
Pick a subject ›